In PBRT 4ed
https://www.pbr-book.org/4ed/Volume_Scattering/Transmittance#eq:volume-attenuation-differential
How is this transmittance equation transformed from 11.9 to 11.10?
\begin{equation} \int_0^d \frac{dL(p + t\omega)}{dt} dt = L(p') - L(p) = \int_0^d -\sigma_t(p + t\omega) L(p + t\omega) dt \tag{11.9} \end{equation}
\begin{equation} T_r(p \to p') = 1 - \int_0^d \sigma_t(p + t\omega) T_r(p + t\omega \to p') dt \tag{11.10} \end{equation}
The book says that dividing 11.9 by L(p) gives 11.10, but the question is why deos Tr convert like that?
Since, \begin{equation} T(p \rightarrow p') = \frac{L(p')}{L(p)} \end{equation}
shouldn't the Tr inside the right integral(11.10) be Tr(p -> p +tw)?
