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Aug 22, 2019 at 9:25 comment added Dan Hulme @gallickgunner That's true. You should be able to tell the difference though, because normally you only get the $L.N$ diffuse contribution approaching zero towards the terminator (or whatever BRDF you use), whereas in this case, you'd also see the $\tfrac{1}{r^2}$ fall-off of the light intensity. You could work out the expected pixel values on the back of an envelope if you could be bothered, but it's probably easier to just debug the code.
Aug 22, 2019 at 6:00 comment added gallickgunner Just wanted to ask, wouldn't the shadow terminator also depend on the intensity of the light? I mean theoretically no, but practically speaking if there is a very dim light we wouldn't be able to perceive the slightly lit up surface above the terminator making it look like the terminator was way up ?
Aug 12, 2019 at 15:29 history answered Dan Hulme CC BY-SA 4.0