Skip to main content
Computer Graphics

Return to Answer

Added answer for second question
Source Link
beyond
beyond
  • 315
  • 1
  • 5

Only one path per sample.

If you had 64 bounces per first hit and 64 per second hit and so forth you'd never get an image.

Edit: And that's why you need to sample each pixel so many times (easily more than 1024 samples) in order to get it to converge, ie get rid of the noise.

As per 2) (from comment below) The 64 primary rays will not hit the same object in the same spot so you will have to calculate everything for each sample.

Only one path per sample.

If you had 64 bounces per first hit and 64 per second hit and so forth you'd never get an image.

Edit: And that's why you need to sample each pixel so many times (easily more than 1024 samples) in order to get it to converge, ie get rid of the noise.

Only one path per sample.

If you had 64 bounces per first hit and 64 per second hit and so forth you'd never get an image.

Edit: And that's why you need to sample each pixel so many times (easily more than 1024 samples) in order to get it to converge, ie get rid of the noise.

As per 2) (from comment below) The 64 primary rays will not hit the same object in the same spot so you will have to calculate everything for each sample.

Source Link
beyond
beyond
  • 315
  • 1
  • 5

Only one path per sample.

If you had 64 bounces per first hit and 64 per second hit and so forth you'd never get an image.

Edit: And that's why you need to sample each pixel so many times (easily more than 1024 samples) in order to get it to converge, ie get rid of the noise.