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Oct 31, 2021 at 15:56 comment added user17337 one thing tell , suppose I have the two parallel lines we see intersects at point X at infinity. It's is theoretical concepts. But when we do projection in practically this X can be treated as normal point. No vanishing point exists.am I correct?
Oct 30, 2021 at 20:55 comment added user17337 one thing tell theoretically those point we said vanishing point during projection they actually projects like normal point? please reply.. I am waiting for your reply.
Oct 30, 2021 at 18:39 comment added joojaa @User4567 Sure, its a asymptotic behaviour. But in practice any point far enough probably qualifies as a vanishing point, because you dont need infinite precision
Oct 30, 2021 at 18:36 comment added user17337 you mean vanishing point doesn't exists. Actually when two parallel lines intersects in infinity they are not actually intersects. During projection normal point projection is possible but vanishing point projection not possible because it is theoretical concepts but practically it isn't exists. And during projection thoses points are actually normal point... Am I correct?
Oct 28, 2021 at 14:14 comment added joojaa @User4567 please join the chat started above. No wanishin point anywhere in any operation
Oct 28, 2021 at 14:13 comment added user17337 what about vanishing point?
Oct 28, 2021 at 14:09 comment added joojaa @User4567 it is typically just transformed to that point trough a matrix ultiplication a divide by z.
Oct 28, 2021 at 14:07 comment added user17337 So how it world co-ordinate to projection plane and it's form? I seem it projects like normal point projection, $(x, y, z) $to $(x_p, y_p, z_p)$?
Oct 28, 2021 at 14:06 comment added joojaa Let us continue this discussion in chat.
Oct 28, 2021 at 14:03 comment added joojaa @User4567 vanishing points are abstract concepts they dont actually exist in any real data.
Oct 28, 2021 at 14:02 comment added user17337 first of all your answer is very difficult to understand.. And I am struggling to understand vanishing point which is already existing in image and it's form.
Oct 28, 2021 at 14:00 comment added joojaa @User4567 Does not matter its just a point like everything else. practical implementations work on practical data. The data you usually have tells how to connect consequtive points. Theres no way to know what form it takes it depends on the implementation details of my rendering engine and how i want to encode my data.
Oct 28, 2021 at 13:56 comment added user17337 but the such image where vanishing point already exist in iamge, like railway track,, so what could be the form of that points?
Oct 28, 2021 at 13:45 comment added joojaa @User4567 im not sure it is a valid question. A vanishing point is caused by two coplanar lines. Any picture can have arbitrarily many vanishing points. Knowing what it is is meaningless for rendering. Projecting is a alternative way of constructing 3d from the way art books teach you to do stuff.
Oct 28, 2021 at 12:52 comment added user17337 can you tell what is form of vanishing point in projection plane? It is normal $(x, y, z)$ in projection plane?
Oct 28, 2021 at 7:10 history edited wychmaster CC BY-SA 4.0
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Oct 27, 2021 at 22:35 history answered joojaa CC BY-SA 4.0