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Oct 16, 2020 at 23:26 comment added Dr. Pontchartrain @Reynolds, I found this equation CurvePoint = (A*W1*(1-t)^2 + B*W2*2t(1-t) + C*W3*t^2) / (W1*(1-t)^2 + W2*2t(1-t) + W3*t^2) My Python interpretation is: p = (a * w1 * (1-t) ** 2 + b * w2 * 2*t (1-t) + C * w3 * t ** 2 ) / (w1 * (1-t) ** 2 + w2 * 2*t (1-t) + w3 * t**2) Would 2t be 2*t? Do I have the rest correct? Also, what would the weights (w values) be for a circular arc? Thank you.
Oct 16, 2020 at 23:14 comment added Dr. Pontchartrain @Reynolds Thank you for the reply. How would I do that with three points and an equation in Python?
Oct 16, 2020 at 23:11 comment added Reynolds This quadratic Bezier curve will not exactly reproduce a circular arc, but only approximate it. To truly represent a circular arch you should use a rational quadratic Bezier curve.
Oct 15, 2020 at 22:37 vote accept Dr. Pontchartrain
Oct 15, 2020 at 22:37 history answered Dr. Pontchartrain CC BY-SA 4.0