9

Given triangle ▲ABC, we bisect angle ∠BAC with line AD, derived with Angle Bisector Theorem: BA / BD = CA / CD Point E represents our objective refined position on the desired resulting inset triangle. As it lies upon angle bisector AD, it is equidistant from sides BA & CA, forming identical right triangles ▲AFE & ▲AGE. We can now use Sine for ...


2

Picking up from step 2, where you generated line segments to represent individual stitches, I would first suggest that you apply rounded ends to each segment, rather than square ends. I would then convert each segment to an outline, (i.e. each rounded stitch becomes an separate poly-line representing the outer boundary.) For example, suppose you start with ...


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