New answers tagged interpolation
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I4=I1( 1-t ) + t.I2 ; from parametric equation of line
I4=I1 - I1.t + t. I2
I4=I1+ t (I2-I1)
Let's take line AB apart from triangle
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Since this is linear interpolation it boils down to solving a linear equation
$y = a + b t$
You can substitute the following $y = y_s$, $a = y_1$(intercept) and $b = y_2 - y_1$ (slope) to get the following
$$y_s = y_1 + t(y_2 - y_1)$$
$$y_s - y_1 = t(y_2 - y_1)$$
$$\frac{y_s - y_1}{y_2 - y_1} = t$$
The same thing happens for points where you can write
$$D = ...
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