# Tag Info

8

Using physically based BRDFs only makes sense if your entire pipeline is built for physical units - the extreme range of values can't be displayed properly without some form of tone mapping. You didn't include that part of the code but from the looks of it I'd say you're doing a simple clamp() followed by linear->sRGB conversion, which causes the bad ...

1

If this was correct, $\frac{D(H)G(L,V,H)}{4|N⋅V|}$ should be a dirac delta function. But I don't think so. Actually, you're close to your answer - you just are trying to find out, what the assumption was in the very beginning - if you're talking about a specular BRDF. The term $F\frac{DG}{4|N⋅V||N⋅L|}$ only works, if you start with the precondition, that ...

1

After coming back to the problem now with a fresh pair of eyes, I have managed to find my mistake. Ad Question 1 Yes, the formula is correct. The problem is hidden in the tangent and bi-tangent . When performing normal mapping, the tangent frame has to be perpendicular to the mapped normal, otherwise the term will not carry any information about the ...

1

In microfacet BRDFs, the half-vector is the same as the microfacet normal. The half-vector is exactly the required normal for a microfacet to reflect light from the incident ray to the outgoing ray, by the law of reflection. So, for given incident and outgoing directions, only those microfacets whose normals are aligned with the half-vector are "active". ...

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