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In line drawing, bresenham's algorithm was explicitly derived for lines with slopes between 0 and 1 in the first octant from point P1 to point P2, where the x value of P1 is less than that for P2.

In the incremental version of this algorithm, once a pixel is drawn, we need to choose the next pixel to draw.

What are the choices? How do we go about choosing which pixel to draw next? (assuming a line width of 1 pixel)

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Well, for the first octant you can either step EAST or NORTH-EAST. Depending on the distance to the actual line you choose the appropriate. In many integer implementations, this is done with regard to the sign of D.

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  • $\begingroup$ But why doesn't it work for lines with slopes greater than 1 though? $\endgroup$ – user9778 Dec 7 '18 at 23:26
  • $\begingroup$ How would we actually accomplish drawing these lines with slopes greater than 1 persay $\endgroup$ – user9778 Dec 7 '18 at 23:29
  • $\begingroup$ The code only caters for the first octant by design. Well, this is easy to understand if you draw a line in the second octant. Here you will have to mirror the code in y=x, broadly speaking, or in other words step NE and N. This is the sign (dx) and sign (dy) you see in the implementations online. $\endgroup$ – beyond Dec 9 '18 at 0:26

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