I was curious so I tried it. I used the Kaiser Window from Wikipedia: $\frac{I_0\left(\alpha\sqrt{1-x^2}\right)}{I_0\left(\alpha\right)}$
This page has a slightly different formulation using $\pi\alpha$ instead of $\alpha$. Given the comments in the page you linked about the Kaiser window being very similar to Lanczos and how they even overlap in the graph, I suspect they also used the former formula. You can see how close they are if you plot both on Wolfram.
This left me wondering if that's what Mitchell originally meant as it's not "noticably better". I could not see the difference at all with my test texture (it's there, just not noticeable). However, using the second formula, the difference in the plots is much more striking. And there is a noticeable difference in the resulting images. Whether it's better is a matter of interpretation and depends on the filter size.
With $x \in \left[-1,1\right]$ , I used this C++ windowing function:
#include <boost/math/special_functions/bessel.hpp>
float bessel_i0( float x )
{
return boost::math::cyl_bessel_i( 0, x );
}
float window_kaiser( float x )
{
const float alpha = 4.0f * M_PI;
float k =
bessel_i0( alpha * sqrtf( 1.0f - x * x ) ) /
bessel_i0( alpha );
return k;
}
This is the second version. Remove the M_PI
to get the first version which is more like Lanczos.
The modified Bessel function of the first kind seems to be a C++17 / boost thing. If you have neither, this quick hack will do:
float bessel_i0( float x )
{
float r = 1.0f;
float term = 1.0f;
for( int k = 1; true; ++k )
{
float f = x / float(k);
term *= 0.25f * f * f;
float new_r = r + term;
if( new_r == r )
break;
r = new_r;
}
return r;
}
Just don't consider that a general replacement for a proper bessel function. However, it's fine for computing the window as far as I could tell.
As the second wikipedia page I linked shows, that window_kaiser
can be used on a symmetric filter with $N$ weights by using $x = \frac{2n}{N-1}-1$, where $n$ is $0, 1, 2 \dots N-1$.
Computing the weights of the sinc filter itself is another thing entirely as it depends on filter size, how much you're resizing, etc. I suggest posting a separate question if you don't know how do to that.