4
$\begingroup$

I'm trying to implement Weighted, Blended Order-Independent Transparency

There are three passes:

  1. 3D opaque surfaces to a primary framebuffer
  2. 3D transparency accumulation to an off-screen framebuffer
  3. 2D compositing transparency over the primary framebuffer

I need to test transparent objects against default depth buffer. I created a framebuff for transparency pass and also created a depth buffer for maybe I can copy default depth to this buffer if this is the only way. But I don't know how to do that because I created depth buffer with GL_DEPTH_COMPONENT24 but I don't know default depth format.

Is it possible to bind default framebuffer's depth buffer to another framebuffer? If not, how can I copy default depth to another depth buff, or what is best way to do this?

$\endgroup$

1 Answer 1

3
$\begingroup$

Is it possible to bind default framebuffer's depth buffer to another framebuffer?

First, you "attach" images to framebuffers. You "bind" objects to the context; you "attach" objects to other objects.

Second, no, you cannot attach images of the default framebuffer to anything.

If not, how can I copy default depth to another depth buff, or what is best way to do this?

You render to your own depth buffer entirely. Just copy/render the image data out to the default framebuffer when its time to display it.

$\endgroup$
3
  • $\begingroup$ what about glBlitFramebuffer? Can't I copy default framebuffer's images or depth to another framebuffer with it? $\endgroup$
    – recp
    Commented Feb 7, 2018 at 18:03
  • 1
    $\begingroup$ @recp: Yes, you could. Or you could just render to your own image and not have to do a copy. Why pick the slower option? $\endgroup$ Commented Feb 7, 2018 at 20:15
  • $\begingroup$ "Why pick the slower option?" maybe this is what I was looking for. I don't know which one is faster so I tried to save texture space. As a solution I will render opaque objects to another framebuff and share its depth buffer with transparency framebuff, this seems better way and fits with your answer I guess $\endgroup$
    – recp
    Commented Feb 7, 2018 at 20:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.