# Find the formulas of the middle point algorithm for drawing the parabola?

Find the formulas of the middle point algorithm for drawing the parabola ?
x^2 = 4*(a+b)*y , a,b > 0.
Solve it according to E(East) and NorthEast(NE) ?

This is the result i got (This is writen in java frame, so its the opposite on graph) This is my try, Ok in this problem the y increases y_{k+1} = y_k + 1 every time and x_{k+1} = x_k or x_k + 1 depending on the P_k value. Here is code i tried with: If P_{k} > then ( p_{k+1} = p_k - 4*(a + b) + 2x_k + 1; and x in increased by one x_{k+1} = x_k + 1;) else ( p_{k+1} = p_k - 4(a + b);) , It doesn't look very well i think

• This is obviously a homework/exercise question. So can you tell us what you have tried by yourself and what you are struggling with? I searched the internet for "middle point algorithm parabola" and already got some promising results. Just copy-pasting the question is at least for me a bit to less effort on your side to be willing to help. – wychmaster Jul 8 '20 at 6:17
• I'll send you what i archieved today later cause i am busy with some other things, thank you for helping. – MrJab Jul 8 '20 at 6:30
• youtube.com/watch?v=Y0Onvip-j9w ... By watching this video this is my try, Ok in this problem the y increases y_{k+1} = y_k + 1 every time and x_{k+1} = x_k or x_{k+1} depending on the P_k value. Here is code i tried with: If P_{k} > then ( p_{k+1} = p_k - 4*(a + b) + 2*x_k + 1; and x in increased by one x_{k+1} = x_k + 1;) else ( p_{k+1} = p_k - 4*(a + b);) , It doesn't look very well i think.. – MrJab Jul 8 '20 at 9:16
• I added the photo i got in code – MrJab Jul 8 '20 at 9:17