6
$\begingroup$

I wish to understand the specific application of Multiple Importance Sampling (MIS) to weighting BSDF sampling and light sampling together. Refer to the following diagram from these Stanford course notes:

Multiple Importance Sampling

I understand the source of noise in the left diagram (a), but not in the right (b), and I think this stems from understanding what "sampling the BSDF" means, but not understanding what "sampling the light sources" means.

To confirm my understanding I'm going to grossly simplify the general path tracing procedure, and specialize it to a single bounce in this scene, to get the point across:

BSDF sampling (diagram (a)) procedure:

  • Cast a ray from the camera for a given pixel.
  • Upon hitting the glossy surface, sample the surface's BSDF, then continue along the newly sampled ray.
  • Hopefully, you hit the light, in which case you contribute energy to the given pixel.

This will obviously yield the noise profile we see in diagram (a); the noise goes down as the surface gets glossier (sharpening the distribution of the BSDF) and as the light gets bigger (making the target easier to hit by chance).

However, I don't understand the nature of the noise in diagram (b), and I therefore clearly don't understand what "sampling the light source" means. My guess would be a procedure like:

Light source sampling (diagram (b)) procedure(???):

  • Cast a ray from the camera for a given pixel.
  • Upon hitting the glossy surface, uniformly sample the solid angle that subtends the light source (i.e., a "shadow ray"), then continue along the newly sampled ray.
  • If you hit the light (i.e., no obstructions) contribute energy to the given pixel, weighted inversely by the BSDF of the glossy surface evaluated at the shadow ray, (and probably also multiplied by some other weight representing the fraction of our total solid angle that the light takes up, as in regular importance sampling).

(Again, I have grossly simplified, and have reduced the problem to a single bounce in this particular scene for illustrative purposes.)

However, the procedure I have described above cannot possibly be what is meant by "light source sampling" in the linked paper, because then it wouldn't result in more noise with larger area lights.

What's going on in diagram (b)?

Edit: I suddenly understood the issue. The noise in the top right corner of (b) is because it's struggling to find the tiny fraction of angles in which the BSDF is not extremely close to zero. My assertion "... because then it wouldn't result in more noise with larger area lights" is precisely wrong, because larger area lights correspond to sampling over a larger fraction of the solid angle, and thus sampling the inverse BSDF weights with higher variance.

I'm now looking for how to delete my question. Hitting the "flag" button just sends me to the top of the page, and doesn't do anything else...

Improve this question
$\endgroup$
1
  • 4
    $\begingroup$ If you have a found an answer to your question, the standard thing to do is to add an answer explaining what was going on. You normally wouldn't delete a question, specially since you would need help from an admin to do that anyways. $\endgroup$
    – Sebastián Mestre
    Oct 17, 2018 at 2:06

1 Answer 1

Reset to default
1
$\begingroup$

Edit: I suddenly understood the issue. The noise in the top right corner of (b) is because it's struggling to find the tiny fraction of angles in which the BSDF is not extremely close to zero.

Yes your reasoning here is correct.

Taken to the extreme if the top most surface was perfectly mirror (dirac delta BRDF), then it would never* sample the right ray from the light source that was perfectly aligned with the camera's view direction. For such a BRDF $\omega_i$ must equal $\omega_o$.

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.